Question

1. x – 3 > –9

2. –2x + 1 ≤ –11

3. 10 < –3x + 1

4. 2(x + 5) > 8x – 8

5. –2(x – 3) ≥ 5 – (x + 3)


Solve each and graph for each

Answer 1

@AbdullahM

Answer 2

1. x> -6

Answer 3

correct :)

Answer 4

how would i graph this

Answer 5

You could use: https://www.desmos.com/calculator

Answer 6

i mean on a number line sorry

Answer 7

it would be an open circle?

Answer 8

yes

Answer 9

Do you have a website for the number line?

Answer 10

essentially, you can use the website and only look at the x-axis

Answer 11

and since you see the graph has a dashed line, that means an open circle.

When the line on the graph is solid, then that means a closed circle.

Answer 12

ok so closed

Answer 13

this has a dashed line so it means open circle

Answer 14

I drew an orange box around the dashed line.

Answer 15

alright i can graph the rest i just need help solving the rest

Answer 16

-2x +1 < -11 \[-2x +1 \le -11\]

Answer 17

for graphing it on a number line:

Answer 18

For #2, we would first take the +1 to the other side. So we have to subtract that on both sides.

Answer 19

so -12

Answer 20

-2x less than or equal to -12

Answer 21

now we have
\(\sf -2x\le -12\)

Answer 22

now devide -2?

Answer 23

divide*

Answer 24

Do you know that when you divide by a negative number on both sides that the sign flips

Answer 25

so it goes to
>?

Answer 26

or this

Answer 27

For example:

\(\sf\Large -x \le 5\)
then
\(\sf\Large x \ge 5\)

another example:

\(\sf\Large -2y > 6\)
then
\(\sf\Large y<-3\)

Answer 28

does it ever switch from \[\le \to \]

Answer 29

not showign up

Answer 30

without the line under it

Answer 31

no it can't

Answer 32

but this answer is x=6

Answer 33

\(\color{blue}{\text{Originally Posted by}}\) @AbdullahM
now we have
\(\sf -2x\le -12\)
\(\color{blue}{\text{End of Quote}}\)

if we divide -2, and also we have to change the sign, what do we get?

Answer 34

x= 6

Answer 35

oh x > 6

Answer 36

no, it would be \(\sf\Large x\ge6\)

Answer 37

yeah thats i meant my b

Answer 38

could i also say greater than or equal to?

Answer 39

remember

these are the opposites:

\(\sf \le\) and \(\sf \ge\) are opposites
< and > are opposites

Answer 40

and this circle would be open?

Answer 41

nope closed

Answer 42

http://prntscr.com/7ln08a

from: http://www.studyzone.org/mtestprep/math8/a/graphing_inequalities7l.cfm