Question

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Consider the following equilibrium:
4KO2(s) + 2H2O(g) 4KOH(s) + 3O2(g)
Which of the following is a correct equilibrium expression?

Keq=[KOH]4[O2]3[KO2]4[H2O]2

Keq=[H2O]2[O2]3

Keq=[KO2]4[H2O]2[KOH]4[O2]3

Keq=[O2]3[H2O]2

Answer 1

for equilibrium expressions, we do not include solids or liquids

so, our equilibrium expression becomes

Keq = [O2]^3/[H2O]^2

Answer 2

Thank you soo much