Question

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The rate law for a hypothetical reaction is rate = k [A]2. When the concentration is 0.10 moles/liter, the rate is 2.7 × 10-5 M*s-1. What is the value of k?

2.7 × 10-3

2.7 × 10-3 M-1s-1

7.2 × 105 M-1s-1

2.7 × 10-4 M-1s-1

Answer 1

K[a]^2 = r

r/[a]^2 = k

2.7x10^-5 M s^-1/(.10)^2 M^2 =2.7x10^-3 M^-1 s^-1