HELP PLEASE. Determine if the graph is symmetric about the x-axis, the y-axis, or the origin.
r = -5 - 5 cos θ
Origin only
x-axis only
y-axis only
No symmetry
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OpenStudy (anonymous):
@dan815 @phi @Hero @Miss.SweetiePie
OpenStudy (anonymous):
@paki
OpenStudy (campbell_st):
have you graphed the curve..?
OpenStudy (anonymous):
yes @campbell_st
OpenStudy (campbell_st):
is it polar coordinates..?
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OpenStudy (anonymous):
idk
OpenStudy (anonymous):
I got x-axis only
OpenStudy (campbell_st):
well can you post your graph...?
OpenStudy (anonymous):
after replacing θ with -θ ...
r = -5 - 5 cos(-θ)
which means that both are even function so that cos(-θ) = cos(θ)
r = -5 - 5 cos θ
OpenStudy (anonymous):
@Miss.SweetiePie thank u so much!!!
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OpenStudy (campbell_st):
lol...
OpenStudy (anonymous):
Your welcome @em2000 are you a fan yet?
OpenStudy (michele_laino):
we can rewrite thhat equation, using the cartesian coordinates, namely:
\[\Large r = - 5 - 5\frac{x}{r}\]
from which we get:
\[\Large {x^2} + {y^2} + 5\sqrt {{x^2} + {y^2}} + 5x = 0\]
Now it is easy to understand if there is a symmetry for that equation