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The average cricket jumps vertically with an inital upward speed of 10 ft/s. What is the hang time of such a jump, ignoring air resistance? Use the formula h=-16t^2+10t, where h is the height of the cricket in feet and t is the time in seconds after the jump. Round your answer to the nearest tenth.

A.
0.4 seconds
B.
0.6 seconds
C.
0.8 seconds
D.
1.0 second

Question

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The average cricket jumps vertically with an inital upward speed of 10 ft/s. What is the hang time of such a jump, ignoring air resistance? Use the formula h=-16t^2+10t, where h is the height of the cricket in feet and t is the time in seconds after the jump. Round your answer to the nearest tenth.

A.
0.4 seconds
B.
0.6 seconds
C.
0.8 seconds
D.
1.0 second

anonymous · Answer

am saying A but not sure or B

compassionate · Answer

Hi, 

What would you define as, "Hang time."

anonymous · Answer

time in the air

compassionate · Answer

So you know it travels at 10 ft/s

You're given the formula
 h=-16t^2+10t


What do you think you should do? HINT: The Quadratic Formula

anonymous · Answer

IT has to be A

anonymous · Answer

we calculate the time when h=0
i.e.,initially position and again when it comes on the ground.
$$-16 t^2+10t=0,-2t \left( 8t-5 \right)=0$$
either -2t=0
$$\implies t=0$$
it gives initial time.
or 8 t-5=0
$$t=\frac{ 5 }{ 8 }=0.625$$
it gives final time.
so it is in air ?