Find the vertices and foci of the hyperbola with equation quantity x plus 5 squared divided by 36 minus the quantity of y plus 1 squared divided by 64 equals 1.

Question

anonymous · Answer

@Saisuke<3 Do you know how to do this?

anonymous · Answer

@zepdrix @abb0t

zepdrix · Answer

$$\Large\rm \frac{(x+5)^2}{6^2}-\frac{(y+1)^2}{8^2}=1$$Let's write it like this so we can easily identify our `a` and `b`.

Hmm I don't remember hyperbolas so well :d
gonna look it up real quick.

anonymous · Answer

yas thats how u set it up!!

anonymous · Answer

psh i forgot lol

anonymous · Answer

Ok. Thanks for being the one to finally get back to me @zepdrix

anonymous · Answer

#20minslater

zepdrix · Answer

I'm trying to remember...
we open in the direction of the positive one, ya?

So since our x is the positive, we open left and right?

anonymous · Answer

I believe so

anonymous · Answer

It has been a while for me too @zepdrix I can't get through the whole problem by myself

zepdrix · Answer

Our "center" is being shifted, so that will affect our vertex point here:|dw:1435533631001:dw|