Question

did i do this right?
What is the standard form of the equation of the circle in the graph?

(x - 3)2 + (y + 1)2 = 1
(x + 3)2 + (y - 1)2 = 2
(x + 3)2 + (y - 1)2 = 1
(x - 3)2 + (y + 1)2 = 2

Answer 1

i think its D

Answer 2

What is the center and radius of the circle with equation (x - 5)2 + (y + 3)2 = 16?

center (3, -5); radius = 4
center (-5, 3); radius = 16
center (5, -3); radius = 16
center (5, -3); radius = 4 my answer

Answer 3

(x - 5)^2 + (y - -3)^2 = 4^2
has a center x=5 , y= -3 , r=4

Answer 4

For the the first question, it looks like the circle in the graph has a radius of 1
and a center at x=-3 y=1 (-3, 1)
put those numbers into
\[ (x- h)^2 + (y -k)^2 = r^2 \]

Answer 5

the center is (5,-3) and radius is=4
the standard equation of the circle is.
(x−h)2+(y−k)2=r2
h,k are center and r is the radius

Answer 6

@LynFran are u sure the first one is C?