Mathematics
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OpenStudy (anonymous):
What is the sum of a 7-term geometric series if the first term is 6, the last term is 24,576, and the common ratio is 4?
−32,766
−19,662
19,662
32,766
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OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (anonymous):
i got -32, 766
jimthompson5910 (jim_thompson5910):
\[\Large S_n = a*\frac{1-r^n}{1-r}\]
Plug in
a = 6 (first term)
r = 4 (common ratio)
n = 7 (number of terms)
OpenStudy (anonymous):
6* 1-4^7/1-4?
jimthompson5910 (jim_thompson5910):
I think you meant this right?
\[\Large 6*\frac{1-4^7}{1-4}\]
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OpenStudy (anonymous):
yeah!
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
compute that with a calculator
jimthompson5910 (jim_thompson5910):
make sure you use parenthesis
OpenStudy (anonymous):
i got 32766
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jimthompson5910 (jim_thompson5910):
same here
OpenStudy (anonymous):
thanks again
jimthompson5910 (jim_thompson5910):
np
OpenStudy (anonymous):
will you check this one? @jim_thompson5910
OpenStudy (anonymous):
What is the sum of the geometric sequence 1, −6, 36, … if there are 7 terms?
−39,991
−6,665
6,665
39,991 x this one?
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jimthompson5910 (jim_thompson5910):
Yep
\[\Large S_n = a*\frac{1-r^n}{1-r}\]
\[\Large S_7 = 1*\frac{1-(-6)^7}{1-(-6)}\]
\[\Large S_7 = 39,991\]