Stacy prepared 20 different letters to be sent to 20 addresses. For each letter she prepared an envelope with its correct address. If the 20 letters to be put in to 20 envelopes at random, what is the probability that exactly 19 letters will be put in to the envelope with the correct address?
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(1/20)^19 ?
If 19 letters are in the correct envelopes, then the last letter must also be in the correct envelope. The probability of all 20 envelopes in the correct order is 1/20!
:O
yes i agree!
total possibilties - prob of 1 wrong, and prob of 0 wrong
yeah that looks pretty neat, i guess then we can conclude the probability for exactly 19 letters putting in correct envelopes is 0 ?
oh wait lol everything is wring oops xD
@dan815 Could you help with this math question
everything is right*
xD
the probabilitly is 0!
oh its impossible :)
trying to trick us -.-
shame on this question
guess i was partially successful :P
lol
-.-
Hello
What about 19 or above
Could someone Help me http://openstudy.com/study#/updates/55912961e4b0428366270957
At least 19 correct
im half a sleep anyway xD
Then it would be 1/20!
You guys are so mean Please Help :( Could someone Help me http://openstudy.com/study#/updates/55912961e4b0428366270957
total permutations : 20! permutations in favor : 1 so yeah.. 1/20! on cursory thinking, this doesn't look like a binomial distribution, so other cases can get complicated hmm
try 10 to be correct ?
Question: you have 20 envelopes and 20 letters; 19 are correct matching. Is it not that 20 are matching?? Since 19 right, how can the rest is wrong?
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