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Find x. Round to the nearest tenth if necessary. Assume that segments that appear to be tangent are tangent. x(x+5)=2(2+10)
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HI!
not clear what that tangent part means, but if it is \[x(x+5)=2(x+10)\] then when you multiply out you get \[x^2+5x=2x+20\]which is a quadratic
set equal to zero \[x^2+3x-20=0\] then the quadratic formula
then what would I do after that ? @misty1212
do you know the quadratic formula?
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oh dang i made a mistake!!
is this the original question \[x(x+5)=2(2+10)\]??
if so, then it is just \[x^2+5x=24\]so \[x^2+5x-24=0\] a totally different equation
this one is much easier factor as \[(x-3)(x+8)=0\] and now you can find the zeros easily
yes! thank you @misty1212
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