can someone help me solve this (easy but haven't done it in a while)

Question

xcharlizea · Answer

sure thing boo thangg

math2400 · Answer

$$0.27 = \frac{ 110^2 }{ (y-111)^2 (y-55) }$$

xcharlizea · Answer

o wtf

xcharlizea · Answer

lmaoo hold up gimme a min

zepdrix · Answer

What are we doin? +_+
solvin for y?

math2400 · Answer

yes haha

zepdrix · Answer

Multiply and divide some things,$$\Large\rm (y-111)^2 (y-55)= \frac{ 110^2 }{0.27  }$$Then I guess expand out all those brackets.

zepdrix · Answer

Then you get a cubic.... which.... might be hard to solve :d hmm

math2400 · Answer

wait it's supposed to be (y-110)^2 lol not 111/ but how do u do a cubic? LOL

zepdrix · Answer

$$\Large\rm (y-110)^2 (y-55)= \frac{ 110^2 }{0.27  }$$Well you know how you have your nice `quadratic formula` for dealing with squares?
x= -b+/-sqrt(b^2-....

Well there is one for cubics, but it's extremely long and complex, not worth using most of the time.

We could try applying rational root theorem to find a factor, and then factor it.
If it doesn't factor, then..... oh boy +_+

math2400 · Answer

what is the equation for cubic? lol i think my professor wants us to know

zepdrix · Answer

i doubt it :) lol http://www.math.vanderbilt.edu/~schectex/courses/cubic/

zepdrix · Answer

it's the formula that's taking up two lines

zepdrix · Answer

near the top

zepdrix · Answer

or you could just cheat and use wolfram +_+ https://www.wolframalpha.com/input/?i=%28y-110%29%5E2%28y-55%29%3D110%5E2%2F0.27

zepdrix · Answer

it's a weird solution.. not one we could've come up with just by checking roots and stuff :d

zepdrix · Answer

There is probably some calculus techniques you could use to get really close to the solution... blah