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OpenStudy (anonymous):

The next three batters on a baseball team have hit percentages of 0.325, 0.250, and 0.275, respectively. What is the probability that the first and third batters will both get a hit, while the second batter does not?

OpenStudy (anonymous):

multiply

OpenStudy (anonymous):

actually first compute the probability that the second batter does not get a hit, which is \(1-.25\) then multiply

OpenStudy (anonymous):

I'll add that the possible answers are A. 0.067 B. 0.201 C. 0.217 D. 0.603

OpenStudy (anonymous):

and ill try that

OpenStudy (anonymous):

\(1-.25=.75\) multiply \[0.325\times 0.75\times 0.275\] it should be a pretty small number

OpenStudy (anonymous):

0.067ish? that sounds about right

OpenStudy (anonymous):

looks good to me

OpenStudy (anonymous):

Thanks!

OpenStudy (anonymous):

yw

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