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How many grams of solid NaCN have to be added to 1.2 L of water to dissolve 0.12 mol of Fe(OH)3 in the form of Fe(CN)6^3−? (For simplicity, ignore the reaction of CN− ion with water.) Ksp for Fe(OH)3 is 2.8 × 10^–39, and Kform for Fe(CN)6^3− is 1.0 × 10^31. If someone understands how to do it please help me!
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