Question

If h(x)=(fog)(x) and h(x)=4(x+1)^2 find f(x) and g(x).

Answer 1

it has not a unique solution ,if we don't know about f(x) , or g(x)
for example
\[f(g(x))=4(x+1)^2\\f(x)=4x^2 ,g(x)=x+1\\ \space another \\f(x)=x^2 , g(x)=2x+2 \rightarrow f(2x+2)=(2x+2)^2=4 (x+1)^2\\-\space another -one\ \\f(x)=4x ,g(x)=(x+1)^2\\]

Answer 2

\[f(g(x))=4(x+1)^2\\f(x)=4x^2 ,g(x)=x+1\\ \space another \\f(x)=x^2 , g(x)=2x+2 \rightarrow f(2x+2)=(2x+2)^2=4 (x+1)^2\\-\space another -one\ \\f(x)=4x ,g(x)=(x+1)^2\\\]

Answer 3

I'm confused. is the answer f(x)=4x2,g(x)=x+1 or f(x)=4x,g(x)=(x+1)2 ? I attached the answer choices. thanks!!

Answer 4

ok , it suffices to check all the choices

Answer 5

find it ?

Answer 6

nope, i'm really confused still :/

Answer 7

is it A?

Answer 8

fml it's actually d if anyone is wondering.