If h(x)=(fog)(x) and h(x)=4(x+1)^2 find f(x) and g(x).

Question

amoodarya · Answer

it has not a unique solution ,if we don't know about f(x)  , or g(x)
for example 
$$f(g(x))=4(x+1)^2\f(x)=4x^2 ,g(x)=x+1\ \space another \f(x)=x^2 , g(x)=2x+2 \rightarrow f(2x+2)=(2x+2)^2=4  (x+1)^2\-\space another -one\ \f(x)=4x ,g(x)=(x+1)^2$$

amoodarya · Answer

$$f(g(x))=4(x+1)^2\f(x)=4x^2 ,g(x)=x+1\ \space another \f(x)=x^2 , g(x)=2x+2 \rightarrow f(2x+2)=(2x+2)^2=4 (x+1)^2\-\space another -one\ \f(x)=4x ,g(x)=(x+1)^2\$$

anonymous · Answer

I'm confused. is the answer f(x)=4x2,g(x)=x+1 or f(x)=4x,g(x)=(x+1)2 ? I attached the answer choices. thanks!!

amoodarya · Answer

ok , it suffices to check all the choices

amoodarya · Answer

find it  ?

anonymous · Answer

nope, i'm really confused still :/

anonymous · Answer

is it A?

anonymous · Answer

fml it's actually d if anyone is wondering.