Question

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Answer 1

you can solve this using kinematics for an uniform acceleration:
\(x=v_0t+\frac{1}{2}at^2\)
the final position here is \(x=60m\)
the values for acceleration and initial speed are also given in the problem...

Answer 2

Given: average velocity= -7.5m/s/s, d=60m, initial velocity= 108km/h, final velocity=N/A, Time=?
Always remember this rule, the variable NOT/ N/A given to you is the formula your gunna use to figure out time. In this case it's gunna be d=Vi X t + 1/2 average velocity X t^2.
Solve for T and your good to go.

Answer 3

here we have to apply this equation:
\[\Large 0 = {v_0} - at\]
where t is the requested time,
v_0=108 Km/hours= 30 meters/second, and
a=7.5 meters/second