Question

Help pleaseeeeeeeeeeee =*(

Answer 1

\[\sqrt{\sqrt{\sqrt{3x}}}=\sqrt[6]{3x}\]\]

Answer 2

think that should be a 8 not 6

Answer 3

so you have
\[\sqrt[8]{3x}=\sqrt[4]{2x}\] raise each side to the power of 8

Answer 4

yes

Answer 5

yeah you are right
it should be \(\sqrt[8]{2x}\)
raise each side to the power of 8 to clear the radicals

Answer 6

\[3x=4x^2\] is what you will get
then solve for \(x\)

Answer 7

hey how did u get that....?

Answer 8

raised both sides to the power of 8

Answer 9

wait what? why?

Answer 10

\[\sqrt[8]{3x}^8=3x\]
\[\sqrt[4]{2x}^8=(2x)^2=4x^2\]

Answer 11

why? to get rid of the radicals

Answer 12

but i don't understand why when the base is different numbers

Answer 13

if you want to get rid of the racial on \(\sqrt[8]{3x}\) it should be pretty clear you have to raise it to the power of 8 right?

Answer 14

lol "radical"

Answer 15

no i don't understand that part is that like a rule or something?

Answer 16

when r u allowed to do that? when they're both divisible by the same number?

Answer 17

how else can you do it? you have the eighth root
if you want to get it without the eighth root you have to raise it to the power of 8

Answer 18

what else can you do?

Answer 19

so you just come up with the 8 out of thin air? there isn't a rule or anything?

Answer 20

no , it was the eighth root
if it was the fifteenth root, you would have to do something different

Answer 21

.... omg im so lost and nervous

Answer 22

I'm seriously not understanding that part

Answer 23

how are you going to get the \(3x\) outside of the radical ? you have
\[\sqrt[8]{3x}\]
what can you do to get rid of that radical?

Answer 24

if you square it, you would still have a radical wouldn't you ?