What is the value of b? 90 75 80 100
@TrojanPoem
@ganeshie8 can u please help me?
Sorry I am checking other question so mixing up. give me a second.
ok
hmm is "b" meant to be on a tangential line?
that is |dw:1435704514383:dw|
idk
maybe
hmmm
so... got any ideas on what "a" is?
no..
something tells me is not a tangent :/
ok hmmm http://jwilson.coe.uga.edu/emt668/EMAT6680.2003.fall/Nichols/6690/Webpage/Day%204_files/image016.gif <--- notice that "inscribed angle and intercepted arc" theorem what do you think "a" is?
let us assume that line is a tangent
ok..
so.. using that theorem... what would you get for "a"? what is m<a?
notice, that theorem plainly says the inscribed angle, is HALF of the intercepted arc
i cant figure out how exactly to find it.. do i need a to find b?
so.... using that... what would we get for "a"?
55?
55? well.. how did you get 55 then?
isnt it half of 110?
well.. how does 110 come in?
idk i thought thats what u were talking about.. im confused
notice the "intercepted arc" from the "inscribed angle" \(\measuredangle a\)
so.. that makes "a" = ?
90?
@jdoe0001 this one
hmm ahemm nope check the "intercepted arc and inscribed angle" theorem "a" is inscribed and is intercepting an arc that is 90 degrees... thus angle "a" is ?
i looked up inscribed angle thereom: The inscribed angle theorem states that an angle θ inscribed in a circle is half of the central angle 2θ that subtends the same arc on the circle. Therefore, the angle does not change as its vertex is moved to different positions on the circle.
and so... "a" gives us?
45?
right?
"a" is half of the intercepted arc, so yes the arc is 90, the angle is half that, or 45 so hmmm one sec
yes. Ok.
anyway so using another theorem of a tangent hitting a chord |dw:1435707709250:dw|
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