Question

What is the surface area of the cone?

175π cm2
224π cm2
147π cm2
273π cm2

Answer 1

im using this site http://www.web-formulas.com/Math_Formulas/Geometry_Surface_of_Cone.aspx but got the wrong answer and kind of confused how to put it all in the formula..

Answer 2

A=πr(r+h2+r2)

Answer 3

\(\large \textit{volume of a cone}=\cfrac{\pi r^2 h}{3}\qquad
\begin{cases}
r=radius\\
h=height
\end{cases}
\)

Answer 4

hmm shoot .. surface area... ok

Answer 5

13891 9/25?

Answer 6

@NathalyN

Answer 7

\(\bf \textit{total surface area of a cone}=\pi r\sqrt{r^2+h^2}+\pi r^2\qquad
\begin{cases}
r=radius\\
h=height
\end{cases}
\)

Answer 8

16909.214?

Answer 9

or 703.36 those are the answers im getting..

Answer 10

hmm so.. which one did you get?

Answer 11

https://www.google.com/search?client=opera&q=pi*7*sqrt(7%5E2%2B24%5E2)%2Bpi*7%5E2&sourceid=opera&ie=utf-8&oe=utf-8&channel=suggest&gws_rd=ssl

Answer 12

so \[3.14*7\sqrt{7^{2}}+24^{2} + 3.14*7^2 =\] 16909.214

Answer 13

yeah and i got that answer u got by doing it another way.. but none of those are on my answer choices..

Answer 14

@jim_thompson5910

Answer 15

ohh hmmm your choices are in \(\huge \pi\) terms
thus... you need to keep the \(\huge \pi\) without multiplying it

Answer 16

so how do i do that?

Answer 17

well.. just don't multiply the \(\pi\) and keep it as is, as a variable per se

Answer 18

\[7*\sqrt{7^2+24^2} + 3.14*7^2\]

Answer 19

or wait..

Answer 20

one sec

Answer 21

\[7*\sqrt{7^2+24^2} * 7^2 = 8575\]

Answer 22

okay.. still lost

Answer 23

hmmm have a typo there one sec \(\bf \textit{total surface area of a cone}=\pi r\sqrt{r^2+h^2}+\pi r^2\qquad
\begin{cases}
r=radius\\
h=height
\end{cases}
\\ \quad \\
\pi r\sqrt{r^2+h^2}+\pi r^2\implies \pi r(\sqrt{r^2+h^2}+r)\impliedby \textit{common factor}
\\ \quad \\

\begin{cases}
r=7\\
h=24
\end{cases}\implies \pi \cdot 7(\sqrt{7^2+24^2}+7)\implies \square ?\pi \)

Answer 24

224?

Answer 25

yeap

Answer 26

thank you

Answer 27

so in \(\pi\) terms is \(\large 224\pi\)

Answer 28

Can u finish helping me on my other question please?