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OpenStudy (anonymous):
How many milliliters of 6M NaOH must be diluted to prepare 2.0 liters of 1.2M NaOH. Please help me get this problem started...
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OpenStudy (photon336):
\[M _{1} V _{1} = M _{2}V _{2}\] \[\frac{ 2.0 l x1.2M }{ 6M NaOH } = 0.4L \]
OpenStudy (photon336):
0.4L = 400 mL
OpenStudy (anonymous):
So where do you get the 0.4L?
OpenStudy (anonymous):
got it thanks!
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