Mathematics
7 Online
OpenStudy (anonymous):
What is the value of w in terms of x and y?
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OpenStudy (anonymous):
aka "solve for \(w\) " right?
OpenStudy (anonymous):
|dw:1435716265419:dw|
OpenStudy (anonymous):
I'm not sure...
OpenStudy (anonymous):
if that is a straight line on the right, then \(2x+w=180\)
OpenStudy (anonymous):
yea
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OpenStudy (anonymous):
so you can solve for \(w\) with no \(y\) in it , just
\[w=180-2x\]
OpenStudy (anonymous):
The answer to this is w=2x+2y-180
OpenStudy (anonymous):
i have no clue how that's the answer
OpenStudy (anonymous):
me neither
OpenStudy (anonymous):
crap
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OpenStudy (anonymous):
i am sure we can figure it out if we stare long enough
OpenStudy (anonymous):
yea that's the only strategy i have thus far
OpenStudy (anonymous):
we got a bunch of stuff we know
for example \[x+y+k=180\]
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
\[w+2k=180\]
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OpenStudy (anonymous):
yea i got that
OpenStudy (anonymous):
we can solve \[w+2k=180\] for \(k\) and get
\[w=180-2k\]then plug that in to the first one
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
oops that is wrong, i meant "solve for \(k\)"
OpenStudy (anonymous):
\[k=\frac{180-w}{2}\]
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OpenStudy (anonymous):
hmmm okay
OpenStudy (anonymous):
plug that in h ere \[x+y+k=180\]
OpenStudy (kash_thesmartguy):
This is confusing!
OpenStudy (anonymous):
\[x+y+\frac{180-w}{2}=180\] then solve that for \(w\)
OpenStudy (anonymous):
wow u kno what i'm just going to skip this because this is way too hard
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OpenStudy (anonymous):
it is not that hard takes three steps at the most
OpenStudy (anonymous):
multiply by 2 get \[2x+2y+180-w=360\]
OpenStudy (anonymous):
add \(w\) subtract \(360\) get
\[2x+2y-180=w\]
OpenStudy (anonymous):
wow you got it..... okay well lemme sit here and stare for a bit to process this..
OpenStudy (anonymous):
so another method would be
K=(180-x-y)
w+k+k=180
w=180-2k
w=180-2(180-x-y)
w=180-360+2x+2y
w=2x+2y-180