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Mathematics 7 Online
OpenStudy (anonymous):

What is the value of w in terms of x and y?

OpenStudy (anonymous):

aka "solve for \(w\) " right?

OpenStudy (anonymous):

|dw:1435716265419:dw|

OpenStudy (anonymous):

I'm not sure...

OpenStudy (anonymous):

if that is a straight line on the right, then \(2x+w=180\)

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

so you can solve for \(w\) with no \(y\) in it , just \[w=180-2x\]

OpenStudy (anonymous):

The answer to this is w=2x+2y-180

OpenStudy (anonymous):

i have no clue how that's the answer

OpenStudy (anonymous):

me neither

OpenStudy (anonymous):

crap

OpenStudy (anonymous):

i am sure we can figure it out if we stare long enough

OpenStudy (anonymous):

yea that's the only strategy i have thus far

OpenStudy (anonymous):

we got a bunch of stuff we know for example \[x+y+k=180\]

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

\[w+2k=180\]

OpenStudy (anonymous):

yea i got that

OpenStudy (anonymous):

we can solve \[w+2k=180\] for \(k\) and get \[w=180-2k\]then plug that in to the first one

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

oops that is wrong, i meant "solve for \(k\)"

OpenStudy (anonymous):

\[k=\frac{180-w}{2}\]

OpenStudy (anonymous):

hmmm okay

OpenStudy (anonymous):

plug that in h ere \[x+y+k=180\]

OpenStudy (kash_thesmartguy):

This is confusing!

OpenStudy (anonymous):

\[x+y+\frac{180-w}{2}=180\] then solve that for \(w\)

OpenStudy (anonymous):

wow u kno what i'm just going to skip this because this is way too hard

OpenStudy (anonymous):

it is not that hard takes three steps at the most

OpenStudy (anonymous):

multiply by 2 get \[2x+2y+180-w=360\]

OpenStudy (anonymous):

add \(w\) subtract \(360\) get \[2x+2y-180=w\]

OpenStudy (anonymous):

wow you got it..... okay well lemme sit here and stare for a bit to process this..

OpenStudy (anonymous):

so another method would be K=(180-x-y) w+k+k=180 w=180-2k w=180-2(180-x-y) w=180-360+2x+2y w=2x+2y-180

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