Mathematics
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OpenStudy (sloppycanada):
This little guy is annoying.
http://gyazo.com/ae8382ea043cf4d43c5dfc637f165dbf
(x+11.5)^2/30.25 - (y-1.5)^2/4 = 1
10 years ago
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jimthompson5910 (jim_thompson5910):
you're trying to find the equation based on the graph?
10 years ago
OpenStudy (sloppycanada):
I am @jim_thompson5910
10 years ago
jimthompson5910 (jim_thompson5910):
do you see where the left edge of the box is? what x coordinate is this?
10 years ago
OpenStudy (sloppycanada):
-11.5
10 years ago
jimthompson5910 (jim_thompson5910):
I'm thinking -11
10 years ago
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jimthompson5910 (jim_thompson5910):
since it's halfway between -12 and -10
10 years ago
jimthompson5910 (jim_thompson5910):
how about the right edge?
10 years ago
OpenStudy (sloppycanada):
Oh yeah... okay so -11 and 1
10 years ago
jimthompson5910 (jim_thompson5910):
add them up and divide by 2
10 years ago
jimthompson5910 (jim_thompson5910):
doing that gives you what?
10 years ago
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OpenStudy (sloppycanada):
(x+11)^2/9 - (y-1)^2/4 = 1
10 years ago
jimthompson5910 (jim_thompson5910):
\[\Large \frac{-11+1}{2} = ??\]
10 years ago
jimthompson5910 (jim_thompson5910):
doing that calculation gives the x coordinate of the center
10 years ago
OpenStudy (sloppycanada):
-5
10 years ago
jimthompson5910 (jim_thompson5910):
good
10 years ago
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jimthompson5910 (jim_thompson5910):
now do the same for the top and bottom edges
10 years ago
OpenStudy (sloppycanada):
9 - -7/2
8?
10 years ago
jimthompson5910 (jim_thompson5910):
Add not subtract \[\Large \frac{9 + (-7)}{2} = \frac{2}{2} = 1\]
10 years ago
jimthompson5910 (jim_thompson5910):
So the center is (-5,1)
10 years ago
jimthompson5910 (jim_thompson5910):
\[\Large \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1\]
(h,k) is the center
a = half of the horizontal length of the box
b = half of the vertical length of the box
hyperbola looks like this
|dw:1435720969381:dw|
10 years ago