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Mathematics 17 Online
OpenStudy (sloppycanada):

This little guy is annoying. http://gyazo.com/ae8382ea043cf4d43c5dfc637f165dbf (x+11.5)^2/30.25 - (y-1.5)^2/4 = 1

jimthompson5910 (jim_thompson5910):

you're trying to find the equation based on the graph?

OpenStudy (sloppycanada):

I am @jim_thompson5910

jimthompson5910 (jim_thompson5910):

do you see where the left edge of the box is? what x coordinate is this?

OpenStudy (sloppycanada):

-11.5

jimthompson5910 (jim_thompson5910):

I'm thinking -11

jimthompson5910 (jim_thompson5910):

since it's halfway between -12 and -10

jimthompson5910 (jim_thompson5910):

how about the right edge?

OpenStudy (sloppycanada):

Oh yeah... okay so -11 and 1

jimthompson5910 (jim_thompson5910):

add them up and divide by 2

jimthompson5910 (jim_thompson5910):

doing that gives you what?

OpenStudy (sloppycanada):

(x+11)^2/9 - (y-1)^2/4 = 1

jimthompson5910 (jim_thompson5910):

\[\Large \frac{-11+1}{2} = ??\]

jimthompson5910 (jim_thompson5910):

doing that calculation gives the x coordinate of the center

OpenStudy (sloppycanada):

-5

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

now do the same for the top and bottom edges

OpenStudy (sloppycanada):

9 - -7/2 8?

jimthompson5910 (jim_thompson5910):

Add not subtract \[\Large \frac{9 + (-7)}{2} = \frac{2}{2} = 1\]

jimthompson5910 (jim_thompson5910):

So the center is (-5,1)

jimthompson5910 (jim_thompson5910):

\[\Large \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1\] (h,k) is the center a = half of the horizontal length of the box b = half of the vertical length of the box hyperbola looks like this |dw:1435720969381:dw|

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