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Mathematics 20 Online
OpenStudy (anonymous):

Write an equation of hte line, in point-slope form, that passes through the two given points. points(-15, 7)(5,-3) (posting picture of answers)

OpenStudy (anonymous):

OpenStudy (anonymous):

I picked answer C

OpenStudy (jack1):

m = y2-y1/x2-x1 = -10/20 = - 1/2 so yeah, that's the only one with an M value of -1/2

OpenStudy (jack1):

id go C too ;)

OpenStudy (anonymous):

Yay! I get so happy when I get math questions right. :P I'm bad at math. I have 2 more(including this one) i'm not sure of

OpenStudy (anonymous):

this is the last one

OpenStudy (sepeario):

like @Jack1 did, or you could firstly work out the gradient, and substitute the values into a point gradient formula.

OpenStudy (jack1):

a) \(\large y = -16x^2 +15 +110x\) do you know how to find the derivative of this? (y')

OpenStudy (anonymous):

no..

OpenStudy (jack1):

hmmm... k k well idk how else to do it, sorry so: \(\Large y = -16x^2 +15 +110x\) \(\Large y = -16x^{\color{red}{2}} +110x^{\color{blue}{1}} +15x^\color{green}{0}\) \(\Large y' = \color{red}{2} \times-16x^{\color{red}{2}-1} + \color{blue}{1} \times 110x^{\color{blue}{1}-1} +\color{green}{0} \times 15x^{\color{green}{0}-1} \) \(\Large y' = \color{red}{-32x^1} + \color{blue}{110x^0} + \color{green}{0}\) \(\Large y' = \color{red}{-32x^1} + \color{blue}{110} \) this is the gradient

OpenStudy (jack1):

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