Is there a difference between solving an equation using the elimination method instead of the substitution method? really bad at the substitution method, much rather use the elimination.
no, no difference in answers, just difference in the approach, s'all
elimination method takes out a variable (x or y) and then you can just solve (for x or y) meanwhile substitution means x or y has to be something and then it gets plugged back into the first or second equation... combine like terms solve for x or y lalalalal but both procedures should produce the same results.
Oh okay, so if I solve this question - Solve 4x + 3y = 13 by the substitution method. x + y = 4 using substitution I'll get the same answer?
you should get the same answer.
trying to think what would be easier.. ah take the second equation and have either x or y by itself
take x+y = 4 and rearrange it having either x = ? or y = ?
4x + 4y = 16 4x = 16 - 4y 4x = 13 - 3y 16 - 4y = 13 - 3y is this elimination or am i doing it wrong again?
o_O
ok I'll give an example where elimination can be used x+y=2 x-y=5 now use elimination method @Jack1
dont give me that look
;P
2-y = 5+y ...? im serious, i dont remember this properly hey
So for this I got x = 1 and y = 3
then solve for y, yeah?
for my example x+y=2 x-y=5 add the two equations together @Jack1
@sloppycanada that's right when you plug in x =1 and y=3 your equations will be true!
4x + 3y = 13 x + y = 4 since x = 1 and y =3 4(1)+3(3) =13 4+9=13 13=13 Similarly 1+3=4 4=4
right, now i remember, cheers @UsukiDoll
Alright so point is - I don't need to use the sub method when it says too.
thanks!
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