Question

The probabilities of the top-selling menu item of the family restaurants in four towns being vegetarian and different types of non-vegetarian sandwiches are given in the table.

Town Vegetable
Sandwich Non-vegetarian
Chicken Sandwich Non-vegetarian
Ham Sandwich Non-vegetarian
Bacon Sandwich Non-vegetarian
Tuna Sandwich
Town 1 6.63% 5.42% 7.05% 6.19% 5.91%
Town 2 6.84% 7.11% 6.89% 5.69% 6.58%
Town 3 5.97% 6.63% 5.72% 5.86% 5.79%
Town 4 6.54% 5.86% 6.24% 6.24% 6.33%
Total 6.24% 5.77% 6.03% 5.92% 6.27%%


If a family restaurant in Town 2 has a non-vege

Answer 1

Hi BSP!!!!!!!!!

Answer 2

lol

Answer 3

any answers?

Answer 4

If a family restaurant in Town 2 has a non-vegetarian sandwich as its top-selling menu item, what is the probability that it is a tuna sandwich?

21.7%

25.0%

27.4%

62.7%

65.8%

Answer 5

ummmmmmm @paki @SolomonZelman

Answer 6

@zepdrix

Answer 7

@mukushla

Answer 8

@mathmate

Answer 9

Town/ Vegetable
Sandwich/ Non-vegetarian
Chicken Sandwich/ Non-vegetarian
Ham Sandwich/ Non-vegetarian
Bacon Sandwich/ Non-vegetarian
Tuna Sandwich
thats the order

Answer 10

this problem sucks

Answer 11

what grade are you in?

Answer 12

oh...

Answer 13

y

Answer 14

im in 7th

Answer 15

and im in honors so some of this stuff is easy to me but this one

Answer 16

this one is evil

Answer 17

@bsp50150
It's about conditional probability, which you probably just learned.

Answer 18

Hint:
Focus on town 2:
<------------ non-veg----------->
vege tuna
Town 2 6.84% 7.11% 6.89% 5.69% 6.58%
Total of all sandwiches = 33.11% (\(\Omega\))
total of all non-vege = 26.27 (N)
% of tuna = 6.58 (T)

Probability it's tuna(T) sandwich given that it's a non-vege(N)
is given by the conditional probability
P(T|N)=P(T\(\cap\)N)/P(N)