If y =12 when x= 6, find x when y=-24
find a point in a graph?
You would tell whoever gave this question that there isn't enough info.
does y vary directly with x maybe?
does y vary indirectly with x? or you not given anything else?
yes, i want to know too..
Write an inverse variation equation that relates x and y. Assume that y varies inversely as x. Then solve.
\[y=\frac{k}{x}\]
plug in x=6,y=12 to find the constant k
that is the first step then there is another step afterwards
simplify and substitute
okay i plugged everything in..
did you find the constant k?
that was the whole point in pluggin in your first part (x,y)=(6,12)
first pair*
so it'd be -3 ?
the answer is -12?
y=kx 12=k(6) 2=k y=2x -24=2x x=-24/2 x=-12
I think 6(12) isn't -3
thats not even a choice.
\[y=\frac{k}{x} \\ xy=k \\ 6(12) =k\]
do you know how to multiply 6 and 12?
if you don't you can think of it as 12+12+12+12+12+12 (the sum of six 12's)
yes i do thanks but my teacher checked it and she said its right
oh you already did the question?
i did what you said to start off with but then she emailed me back and set it up
ok so when you said -3 you weren't talking about k you were talking about the for x when y=-24
yes
\[xy=k \\ 6(12)=k \\ 72=k \\ \text{ yeah } k \text{ is 72} \\ xy=72 \text{ replaced } k \text{ with } 72 \\ \\ \text{ now what is } x \text{ when } y=-24 \\ -24x=72 \] yep final answer is x=-3 when y=-24
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