The polynomial x 3 + 5x 2 -57x -189 expresses the volume, in cubic inches, of a shipping box, and the width is (x+3) in. If the width of the box is 15 in., what are the other two dimensions? ( Hint: The height is greater than the depth.)
A. height: 19 in. depth: 5 in. B. height: 21 in. depth: 5 in. C. height: 19 in. depth: 7 in.
@SolomonZelman
@DecentNabeel
easy
Can you please help me? I've already answered it wrong once lol @timo86m
@pooja195
maybe polynomial long division will work here. Divide your polynomial by x+3 maybe.
But how do i even get to that part? @timo86m
because usually u have to factor. And you can take x+3 as a hint that it is one of the factors.
This is the factor that i figured out (x+3)(x−7)(x+9)
@timo86m
here is how i picture it in my head You are given x+3. U will need 2 other similar expressions to get a volume call them x+a x+b x+3 <- given And together they form (x+a) * (x+b) * (x+3) = Volume height*depth* width = volume
good job
Where do i go from there? @timo86m
width = 15 so you are told x+3=15 x=15-3 x=12 therefor x = 12 Plug it in :)
(x+3)(x−7)(x+9) X=12
( Hint: The height is greater than the depth.)
|dw:1435797318265:dw| find two other sides
Is it A?
@timo86m
not sure yet
Thank you @timo86m
x+9=12+9=21 x-7=12-7=5
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