Question

multiplying radicals. please help.

Answer 1

\[(\sqrt{2}-\sqrt{-2}) (\sqrt{8}+\sqrt{-2})\]

Answer 2

Use the FOIL method just like (x+2)(x+2)

Answer 3

\[(\sqrt{2}-i \sqrt{2}) (2\sqrt{2}+i \sqrt{2})\]
.
.
.
\[(2\sqrt{2}+\sqrt{2})+i(2\sqrt{2}-2\sqrt{2})\]

Answer 4

i am stuck right there.. because in my mind the i part cancels out.. but i know it is wrong because thats not the answer in the book

Answer 5

\( (\sqrt{2}-\sqrt{-2}) (\sqrt{8}+\sqrt{-2}) \)

FOIL
F = First
O = Outer
I = Inner
L = Last

F
\( (\sqrt{2})(\sqrt{8}) = \sqrt{16} = 4 \)


O
\( (\sqrt{2})(\sqrt{-2}) = 2i \)

Do you see what I am doing here?

Answer 6

\( (\sqrt{2}-\sqrt{-2}) (\sqrt{8}+\sqrt{-2}) \)

FOIL
F = First
O = Outer
I = Inner
L = Last

F
\( (\sqrt{2})(\sqrt{8}) = \sqrt{16} = 4 \)


O
\( (\sqrt{2})(\sqrt{-2}) = 2i \)

I
\( (-\sqrt{2})(\sqrt{-8}) = -4i \)

L
\( (-\sqrt{2})(\sqrt{-2}) = \sqrt{-4} = 2 \)

Do you see what I am doing? Can you put the rest together? It is almost done.

Answer 7

And you left.....

Answer 8

sorry for the late response. it ll be 6-2i

Answer 9

thank you that makes more sense.

Answer 10

Good job correct!!!