a. Use a metric ruler to measure the distances between Robinson and Neale on the map.
b. Using the scale of the map, find the approximate actual distance by air (not by roads), between Robinson and Neale.
c. Approximately how many square miles are shown on this map?

Question

a.  Use a metric ruler to measure the distances between Robinson and Neale on the map. 
b. Using the scale of the map, find the approximate actual distance by air (not by roads), between Robinson and Neale.   
c. Approximately how many square miles are shown on this map?

anonymous · Answer

http://www.intervisualtechnology.us/data/1/12383/texasmap.jpg is the link to the map

misssunshinexxoxo · Answer

Ok please pull out your ruler and mark it down then post it; I'll go over it

misssunshinexxoxo · Answer

2.4 centimeters is what you messaged me; what's the mileage

misssunshinexxoxo · Answer

Looks like 4 miles to me

anonymous · Answer

Thats the part i'm having trouble with. The scale says 0-5 miles, but idk how to incorporate that with the 2.4 centimeters.

misssunshinexxoxo · Answer

Is this an essay question?

anonymous · Answer

no

misssunshinexxoxo · Answer

I think you separate it

anonymous · Answer

@jim_thompson5910

jim_thompson5910 · Answer

So you measured the distance between Robinson and Neale and got 2.4 cm?

anonymous · Answer

yea

jim_thompson5910 · Answer

use a ruler to measure how long the "0-5" bar is

anonymous · Answer

2.1 cm

jim_thompson5910 · Answer

x = actual distance from Robinson to Neale

solve the proportion for x

$$\Large \frac{\text{Actual Distance}}{\text{Distance on paper}} = \frac{\text{Actual Distance}}{\text{Distance on paper}}$$
$$\Large \frac{x}{2.4} = \frac{5}{2.1}$$
$$\Large x = ???$$

anonymous · Answer

5.7

anonymous · Answer

but it says to find the distance by air and not by roads, what about that part?

jim_thompson5910 · Answer

that's the actual air distance

anonymous · Answer

and it would be 5.7 for part C also?

jim_thompson5910 · Answer

measure the width and height of the entire map with the ruler

jim_thompson5910 · Answer

what do you get?

anonymous · Answer

6.8 cm length and width

anonymous · Answer

so do i just multiply that now?

jim_thompson5910 · Answer

well you first have to convert those distances on paper to actual distances

jim_thompson5910 · Answer

by using a proportion like shown above

anonymous · Answer

so then 16.19

anonymous · Answer

i mean 16.19 is the length and width, and multiplying it i get 262.12

jim_thompson5910 · Answer

so you just found that 6.8 cm on paper corresponds to 16.19 miles in actual distance

jim_thompson5910 · Answer

and yeah the approximate actual area is 262.1161 square miles

anonymous · Answer

yea, i set it up like 5/2.1 = x/6.8 is that right?

jim_thompson5910 · Answer

yes it is

anonymous · Answer

cool, thank you!

jim_thompson5910 · Answer

no problem