Question

What is the standard form of the equation of a circle with its center at (2, -3) and passing through the point (-2, 0)?

(x − 2)squared + (y + 3)squared = 5

(x + 2)squared + (y − 3)squared = 25

(x − 2)squared + (y + 3)squared = 25

(x − 2)squared − (y + 3)squared = 5

Answer 1

@Deezzz

Answer 2

@welshfella

Answer 3

@rvc

Answer 4

the general form is

(x - a)^" + (y - b)^2 = r^2

where (a,b) is the center and r is the radius

Answer 5

yes

Answer 6

so you should be able to work out the left side now by plugging in a = 2 and b = -3

Answer 7

and the radius will be the distance between the center and the point (-2,0)

Answer 8

thanks

Answer 9

yw - if you need more help let me know

Answer 10

:) all the best

Answer 11

@Deezzz

Answer 12

@nincompoop

Answer 13

@Hero

Answer 14

@triciaal

Answer 15

In general, the standard form of the equation of a circle is
\((x - h)^2 + (y - k)^2 = r^2\).

In this case, (h,k) = (2,3) and (x,y) = (-2,0). Plug both points in to the equation, then simplify and solve for r.

Next re-write the standard form of the equation, except this time, insert the given center point and the value of r.

Answer 16

ok ill try, thanks