Question

Please help me =*(

Answer 1

\[\frac{ 5x ^{2}+65x+60 }{ x ^{2}+10x-24 }=\frac{ 5x+5 }{ x-2 }\] then which of the following are possible values of x?

-60
-12
-1
1
2
5

Answer 2

what do u think

Answer 3

i have x+1=x+1

Answer 4

the given equation satisfies all real values except

\(x=2,-12\) as

we have in denominators \((x-12)(x-2)\) which would make equation undefined

Answer 5

wait what?

Answer 6

i thought it worked out for all of them

Answer 7

it satisfies all values except \(x=2\) and \(x=-12\)

Answer 8

can u explain why?

Answer 9

because in the denominator u have \(x^2+10x-24=(x+12)(x-2)\)

if u put \(x=2\) or \(x=-12\) the denominator will become zero and

any number divide by zero is undefined.

Answer 10

ohhhh ic

Answer 11

is there an easier way to check the answer?

Answer 12

yes there is

Set the denominator equal to zero and solve
$$
x^2+10x-24=(x+12)(x-2)=0
$$
This helps you find values that x should NOT be

Just be careful. Before you do this, just make sure that none of these terms is cancelled by the numerator.

Answer 13

You never want the denominator equal to zero.