Question

how to write y= 2x^2 + 8x +7 in standard (vertex) form

Answer 1

= 2x^2 + 8x + 7
= 2(x^2+4x) +7
= 2(x^2 +4 +4) + 7 -8
= 2(x+2)^2 -1
Therefore vertex is (-2,-1)....................................

Answer 2

well 1 version of standard vertex form is

\[y = a(x -h)^2 + k\]

so group the terms in x

\[y = (2x^2 + 8x) + 7\]

remove the common factor for the terms in x

\[y = 2(x^2 + 4x) + 7\]

now complete the square in x,

does that make sense?

Answer 3

there you go... someone has given you the answer