Question

For the given quadratic equation convert into vertex form, find the vertex, and find the value for x = 6. y= -2x^2 + 2x +2?

Answer 1

@IrishBoy123

Answer 2

@Michele_Laino

Answer 3

if we make this substitution:
x=6 into your quadratic equation, we get:

\[\Large \begin{gathered}
y = - 2 \times {6^2} + 2 \times 6 + 2 = \hfill \\
\hfill \\
= - 2 \times 36 + 12 + 2 = ...? \hfill \\
\end{gathered} \]

Answer 4

-58

Answer 5

that's right!

Answer 6

So that's the value of x, correct?

Answer 7

that's the value of y, when x=6

Answer 8

So how do we find the value of x and find the vertex?

Answer 9

our task was to find the value of y, when x=6

Answer 10

the general formula of a parabola is:
\[\Large y = a{x^2} + bx + c\]

Answer 11

So there is nothing else to the problem it's done that simple lol

Answer 12

we have to find the coordinates of the vertex, and the vertex form of the equation of your parabola

Answer 13

so, as I wrote before, the general equation of a parabola, whose axis is parallel to y axis, is:
\[\Large y = a{x^2} + bx + c\]
now, please by comparison with the equationof your parabola, what are the coefficients a, b, and c?

Answer 14

6 and -58?

Answer 15

hint: