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Mathematics 17 Online
OpenStudy (chris215):

Ball A moving along a straight line at 2 m/s collides elastically with ball B of same mass moving at -3 m/s. What is the velocity of the balls A and B after collision?

OpenStudy (anonymous):

mass= force times acceleration

OpenStudy (anonymous):

you need conservation of momentum and conservation of kinetic energy equations. Let \(v_{A1}\) be initial velocity for ball A, \(v_{A2}\) be final velocity for ball 2, \(v_{B1}\) be initial velocity for ball B, and \(v_{B2}\) be final velocity for Ball B Momentum Conservation (P = mv, momentum = mass * velocity) \[P_1=P_2\] \[mv_{A1}+mv_{B1}=mv_{A2}+mv_{B2}\] All the masses are the same so they cancel \[v_{A1}+v_{B1}=v_{A2}+v_{B2}\] Plug in numbers for \(v_{A1}\) and \(v_{B1}\) \[2-3=v_{A2}+v_{B2}\] \[-1=v_{A2}+v_{B2}\] KE = ½mv² Do more or less the same thing to create a conservation of kinetic energy equation

OpenStudy (anonymous):

dame idk

OpenStudy (anonymous):

how about this way since it's multiple choice |dw:1435874747318:dw|

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