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The equation of the following? http://gyazo.com/aa5eae5ff2bbdf3232f9e4ec7edcf30f
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\[\frac{ (x-1)^2 }{ 81 } + \frac{ (y+2) }{ 4 } = 1\]
shouldn't it be\(+1\)
and \(-2\)
No because it's the center.
i think the center is \((-1,3)\) actually from the picture what do you think?
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I would agree.
then the first part should have \((x+1)^2\) and the second \((y+3)^2\)
plus, not minus
oops sorry
the second part would be \((y-3)^2\)
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you got that ? center is \((h,k)\) standard form is \[\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1\]
HI!!
i would go with ' \[\frac{(x+1)^2}{81}+\frac{(y-3)^2}{4}=1\]
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