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Mathematics 20 Online
OpenStudy (sloppycanada):

The equation of the following? http://gyazo.com/aa5eae5ff2bbdf3232f9e4ec7edcf30f

OpenStudy (sloppycanada):

\[\frac{ (x-1)^2 }{ 81 } + \frac{ (y+2) }{ 4 } = 1\]

OpenStudy (anonymous):

shouldn't it be\(+1\)

OpenStudy (anonymous):

and \(-2\)

OpenStudy (sloppycanada):

No because it's the center.

OpenStudy (anonymous):

i think the center is \((-1,3)\) actually from the picture what do you think?

OpenStudy (sloppycanada):

I would agree.

OpenStudy (anonymous):

then the first part should have \((x+1)^2\) and the second \((y+3)^2\)

OpenStudy (anonymous):

plus, not minus

OpenStudy (anonymous):

oops sorry

OpenStudy (anonymous):

the second part would be \((y-3)^2\)

OpenStudy (anonymous):

you got that ? center is \((h,k)\) standard form is \[\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1\]

OpenStudy (misty1212):

HI!!

OpenStudy (misty1212):

i would go with ' \[\frac{(x+1)^2}{81}+\frac{(y-3)^2}{4}=1\]

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