Question

how to find solutions of a quadratic trinomial with a discriminant of 40.

Answer 1

Plssssssss helppppppppppp

Answer 2

A general quadratic polynomial:
\[ax^2+bx+c=0\]
The discriminant \(\Delta\):
\[\Delta= b^2-4ac\]

Answer 3

but how do you get the solutions if the discriminant is a positive number, but not a perfect square. I mean I know it has 2 irrational solutions how would you solve it?

Answer 4

the solutions are given from the quadratic formula
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-b\pm\sqrt{\Delta}}{2a}\]

Answer 5

Thank you. That really helps

Answer 6

If you found the discriminant to be positive, +40: then then irrational roots will be
\[x=\frac{-b\pm\sqrt{40}}{2a}\\
\quad=\frac{-b\pm2\sqrt{10}}{2a}\\\]
\[x=\frac{-b+2\sqrt{10}}{2a},\quad \frac{-b-2\sqrt{10}}{2a}\\
\quad =\qquad\qquad\quad,\]

Answer 7

Thank you!!!!