Question

Anyone?? please help! will give metal!
Is my math on this correct?
How many grams of magnesium oxide can be produced when 97.2 g Mg react with 88.5 g O2?

Unbalanced equation: Mg + O2 → MgO

Show, or explain, all of your work along with the final answer.
Balanced equation: 2Mg + O2 --> 2MgO

Mass of Mg = 97.2g Mg
Molar mass of Mg = 24.3050g Mg

Mass of O2 = 88.5g O2
Molar mass of O2 = 32g O2

Mass of MgO = ?
Molar mass of MgO = 40.304g MgO

?g MgO = 97.2g Mg x (1mol Mg / 24.3050g Mg) x (2mol MgO / 2mol Mg) x (40.304g MgO / 1mol MgO)
=97.2 x 2 x 40.304 / 24.3050 / 2 = 161.2g MgO

Answer for first calculation = 161.2g MgO

?g MgO = 88.5g

Answer 1

@thomaster ? is this correct so far?

Answer 2

What compound was your limiting reagent and why?

You always use the limiting reagent to calculate how any grams of products.