Question

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Answer 1

I'm not sure sorry.

Answer 2

Np

Answer 3

x^2 + 4x +x +4 =0
x(x+4) + 1(x+4) =0
(x+1)(x+4)=0
=>x=-1,-4

Answer 4

How do we define radicand?

Answer 5

yeah

Answer 6

Radicand is the discriminate or b^2 - 4ac

and @princeharryyy please do not solely give answers

Answer 7

So If the discriminant is positive, there are two real roots. If it is zero, there is one real root (a double root). And if the discriminant is negative, there are two imaginary roots and no real roots

Answer 8

the radicand is the discriminant

so you need to use

for a quadratic
\[ax^2 + bx + c = 0\]

the discriminant is


\[\Delta = b^2 - 4ac\]

Answer 9

tnks, i'm not in mood as well @whatdoesthismean
by the way discriminate means (The value you want to take the root of)

Answer 10

radical*

Answer 11

By plugging a b and c, you can find the answer to A as it is asking for the DESCRIPTION of the solutions, not the solutions itself

Answer 12

so for the other parts..

Part B the quadratic can be factored

Pact C use the general quadratic formula

Answer 13

as i said before, the descriptions are as follows'\;

So If the discriminant is positive, there are two real roots. If it is zero, there is one real root (a double root). And if the discriminant is negative, there are two imaginary roots and no real roots

Answer 14

Agreed @campbell_st

Answer 15

and when you do part A you have a = 1, b = 5 and c = 4

and if the discriminant is positive there are 2 options

(a) the discriminant is a sqiare number, 1, 4, 9, 16....

then the roots are real, rational and unequal

(b) is the discriminant is not a square number e.g. 3, 7, 10, 15, etc

the roots are real, irrational and unequal

Answer 16

No, youre supposed to try and use the information and solve it

Answer 17

ok... you need

\[\Delta = b^2 - 4\times a \times c\]

the equation have a = 1, b = 5 and c = 4

plug them in post the answer you get..

Answer 18

well

\[\Delta = 5^2 - 4 \times 1 \times 4\]

what is the value of the calculation

Answer 19

ummm can you recheck it

\[\Delta = 25 - 16\]

Answer 20

ummmm I think

\[\Delta = 25 - 16~~~means~~~~\Delta = 9\]

so based on the solution being >0 and a square number, what type of solutions do you have...?