Factor 3x^2y^2 -xy^2-2y^2 Show your work
you know that ^ means exponent right not multiply
@nincompoop
Yeah I need help solving it with steps
Take out the GCF y^2
\(\bf 3x^2y^2 -xy^2-2y^2\implies 3{\color{blue}{ x}}x{\color{blue}{ yy}}-x{\color{blue}{ yy}}-2{\color{blue}{ yy}}\) take the common factor
I'm really confused
hmm \(\bf 3x^2y^2 -xy^2-2y^2\implies 3{x}x{\color{blue}{ yy}}-x{\color{blue}{ yy}}-2{\color{blue}{ yy}}\) rather
I don't even know where to start
y^2(3x^2 - x - 2)
Yes could you please show me the steps
\[\mathrm{Factor}\:-2y^2+3x^2y^2-xy^2:\quad y^2\left(x-1\right)\left(3x+2\right)\]
hmm do you know how to take a common factor?
Nope
well.. then you may want to cover that firstly then
3x^2y^2 -xy^2-2y^2 take out y^2 \[=y^2\left(3x^2-x-2\right)\] \[\mathrm{Factor}\:3x^2-x-2:\quad \left(x-1\right)\left(3x+2\right)\] \[=y^2\left(x-1\right)\left(3x+2\right)\]
3x^2y^2-xy^2-2y^2 -2y^2 +3x^2y^2-xy^2
I just want to put this all together so it won't be difficult for you for your reference: Pulling out like terms : 5.1 Pull out like factors : 3x2y2 - xy2 - 2y2 = y2 • (3x2 - x - 2) Trying to factor by splitting the middle term 5.2 Factoring 3x2 - x - 2 The first term is, 3x2 its coefficient is 3 . The middle term is, -x its coefficient is -1 . The last term, "the constant", is -2 Step-1 : Multiply the coefficient of the first term by the constant 3 • -2 = -6 Step-2 : Find two factors of -6 whose sum equals the coefficient of the middle term, which is -1 . -6 + 1 = -5 -3 + 2 = -1 That's it Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and 2 3x2 - 3x + 2x - 2 Step-4 : Add up the first 2 terms, pulling out like factors : 3x • (x-1) Add up the last 2 terms, pulling out common factors : 2 • (x-1) Step-5 : Add up the four terms of step 4 : (3x+2) • (x-1) Which is the desired factorization
Thank you so much! Could you help on another
Factor x^2+6x+9
\[\mathrm{Factor}\:x^2+6x+9:\quad \left(x+3\right)^2\]
1 Q per thread pls.
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Ok thanks so muc!
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@DecentNabeel x^2 +3x +3x +9
What's after
\[\mathrm{Simplify}\:x^2+3x+3x+9:\quad x^2+6x+9\]
(X+3)(x+3)
\[\mathrm{Simplify}\:\left(x+3\right)\left(x+3\right):\quad \left(x+3\right)^2\]
Happy @kayleeq :)
Wait what happened I'm sorry
Factor x^2 -25
(x-5)(x+5)
Is that all the steps
Is a common factor for all of the x^2
x^2 -25 this formula a^2-b^2=(a-b)(a+b) x^2-5^2=(x-5)(x+5)
Is that all of the steps though I'm so confused
tell me why confused
\[x^2-25=\left(x+5\right)\left(x-5\right)\]
Is that the steps I don't know how to do this I've been at it for forever
you know a^2-b^2=(a-b)(a+b)
do you know this
What are the steps can you please show me with the actual numbers please yes but is am so conus fed with this question please help me
x^2 -25 use this formula:a^2-b^2=(a-b)(a+b): 25=5^2 x^2-5^2=(x-5)(x+5)
MATHEMATICAL FORMULAE Algebra 1. (a + b)2 = a2 + 2ab + b2; a2 + b2 = (a + b)2 − 2ab 2. (a − b)2 = a2 − 2ab + b2; a2 + b2 = (a − b)2 + 2ab 3. (a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca) 4. (a + b)3 = a3 + b3 + 3ab(a + b); a3 + b3 = (a + b)3 − 3ab(a + b) 5. (a − b)3 = a3 − b3 − 3ab(a − b); a3 − b3 = (a − b)3 + 3ab(a − b) 6. a2 − b2 = (a + b)(a − b)
Oooooooooo ok I got that see I just needed some explaination now only the second and third polynomial share a common factor is that correct it is x^2
yes
Ok thank you sooooooooo much
welcome @kayleeq
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