y = −x^2 + 4 y = 2x + 1
How would you solve by elimination or substitution?
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rvc (rvc):
we have : \[\rm y=-x^2+4~ and ~y=2x+1\]
OpenStudy (anonymous):
yes, I don't get how you would solve them though
rvc (rvc):
so we have two values for y
rvc (rvc):
we can put any of those
OpenStudy (anonymous):
like \[-x^2+4=2x+1\]
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rvc (rvc):
yes
rvc (rvc):
now solve further :)
OpenStudy (anonymous):
but how would you subract them. Thats what im stuck on.
rvc (rvc):
here it is :
\[\rm 2x+1+x^2-4\]
OpenStudy (anonymous):
that is what y equals then right?
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rvc (rvc):
no
since when we solve the equation we are left only with x.
then we will put the value of x in any one of the original equation to find the value of y
OpenStudy (anonymous):
Im really stuck then .. how would you find what x and y are?
rvc (rvc):
here it is :
\[\sf x^2+2x-3=0\]
rvc (rvc):
we have to solve the quadratic equation
OpenStudy (anonymous):
I get x = 1, -3
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rvc (rvc):
yep
now put one value at a time in either : y = 2x+1
or
y=-x^2+4