Write the sum using summation notation, assuming the suggested pattern continues. -9 - 3 + 3 + 9 + ... + 81
@hartnn what about this
what would you multiply to current term to get next term ?
add 6?
multiply/add/divide/subtract**
ok
summation of the quantity negative nine plus six n from n equals zero to fifteen summation of negative fifty four times n from n equals zero to fifteen summation of negative fifty four times n from n equals zero to infinity summation of the quantity negative nine plus six n from n equals zero to infinity
those are the choices
ik we can cross out the last 2 because they are infinity and this one ends with 81
yes, adding 6 is correct, so this is indeed an arithmetic series, lets find the n'th term equation for that \(a_n = a_1 +(n-1)d\) we know d - common difference = 6 a1 = 1st term = -9 plug in!
and you're right! this is a finite series, the answer is from 1st 2 choices only :)
-9+6(n-1)
so it would be the first choice?
yes, thats correct :)
thank you again!
welcome ^_^
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