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How to integrate 3^(x+3^x)
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Try U-sub
Okay sure
splitting it up first might help 3^(x+3^x) = 3^x * 3^(3^x) = 3^x * 3^(3x)
So the integral of 3^x is 3^x / ln(3)
\[\int\limits 3^{x+3^x}dx = \int\limits 3^x \times 3^{3^x} dx\] Let \[u=3^x \\ \\ du=3^xln(3)dx\] \[\int\limits 3^u\frac{1}{\ln(3)}du\]
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@welshfella \[\large 3^{(3^x)}~~ \ne~~ 3^{3x}\] right
Oh yes! I got it! The answer is 3^(3^x) / (ln(3))^2 + C
So when I look at these types of problems I should look at splitting up the problem and if I can u-sub something. Thanks
Thank you everyone~
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Yes always think of U-sub first, then followed by other methods if you can't U-sub
@rational - right!
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