make h the subject of the formulae here T=2pi√ H-h/g , please show the steps
hey @ubah just to clarigy: is this ur eqn: \(\Large T=2\pi \sqrt {H-\frac hg}\) ?
\[T = 2\pi \sqrt{\frac{ H-h }{ g}}\] this is what i meant
ah, cool T=2pi√ H-h/g \(\Large T=2\pi \sqrt { \frac {H-h}g}\) \(\Large \frac T{2\pi}= \sqrt { \frac {H-h}g}\) \(\Large (\frac T{2\pi})^2= (\sqrt { \frac {H-h}g})^2\) \(\Large \frac {T^2}{4\pi^2}= \frac {H-h}g\) \(\Large \frac {T^2 \times g}{4\pi^2}= H-h\)
... i think...?
am waiting for the final step
well... u could do some of it if u want ;P all that's left is subtract H from both sides... then flip the signs on both sides so you're left with h = ...something... can u do this?
no @jack1
they all wanna be spoon fed the answers................go figure
sorry @ubah ... it's against OS policy to provide answers, only help HOW to get answers... recommend you revise basic calculus a little more as the last step is pretty basic maths... if it helps: a - x = b solve for x if you can do the above problem you should be able to clue out the final step to solve for h
thanks bro .... have get rid of it
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