Question

@rvc

Answer 1

I need your help :/

Answer 2

i need medals

Answer 3

yes @nopen

Answer 4

it's part c

Answer 5

I got the answer for a and b

Answer 6

Part a.) is OC = OT - CT = R- r

Answer 7

Part b.) is R*sin*theta = r(1+ sin theta)

Answer 8

im extremely sorry
gtg now

Answer 9

we can write this:
\[\Large \begin{gathered}
21 = 2R + R2\theta = 2R + 2R\arcsin \left( {\frac{3}{4}} \right) = \hfill \\
\hfill \\
= 2R\left\{ {1 + \arcsin \left( {\frac{3}{4}} \right)} \right\} \hfill \\
\end{gathered} \]

Answer 10

since:
\[\Large ATB = R2\theta \]

Answer 11

yea I did that but my problem is why am I to taking the 1 with the given angle?

Answer 12

by definition of radians, we have:
\[\Large L = \alpha R\]

Answer 13

http://prntscr.com/7orri3

Answer 14

@dan815 your answer is wrong =_=

Answer 15

@Michele_Laino
I do remember that arc length formula
but what I'm asking is that, if we are given that O is sin theta = 3/4 why are we taking the 1?

Answer 16

what is the answer

Answer 17

2.43

Answer 18

@Michele_Laino what you've written in your answer is exactly the same thing that is written in the solution bank

I simply wanna know why you talking (1 + arcsin(3/4) instead of just arcsin3/4?

Answer 19

*are taking

Answer 20

since I have factored out the quantity 2R

Answer 21

hey michele can you tell me what's wrong in my method, i cant find it