Question

Simplify completely quantity 8 x minus 16 over quantity x squared minus 13 x plus 22 and find the restrictions on the variable.

Answer 1

HI!!

Answer 2

\[\huge\frac{8x-16}{x^2-13x+22}\]?

Answer 3

I got x-5/x+1 as my answer but I don't know what the restriction would be

Answer 4

did you factor the denomiantor?

Answer 5

yes

Answer 6

Sorry I meant 8/x-11

Answer 7

\[x^2-13x+22=(x-2)(x-11)\]

Answer 8

factor the denominator again
hint 2*11 = 22 and 2 + 11 = 13

Answer 9

then cancel and you get what you wrote

Answer 10

But what would be the restrictions?

Answer 11

so your answer is correct
as for the "restrictions" the denominator cannot be zero

Answer 12

\[(x-2)(x-11)=0\\
x=2,x=11\]

Answer 13

so the restrictions are \(x\neq2\) and \(x\neq 11\) because if \(x\) where either of those two numbers, the denominator would be zero, and if you try to divide by zero you will explode

Answer 14

Ok. I need to ask another one

Answer 15

Simplify completely quantity x squared plus 4 x minus 45 all over x squared plus 10 x plus 9 and find the restrictions on the variable.

Answer 16

lol the equation tool below is very useful

Answer 17

I got x-5/x+1

Answer 18

Sorry

Answer 19

\[\huge \frac{x^2+4x-45}{x^2+10x+9}\]

Answer 20

your answer is correct

Answer 21

yes:) What would be the restrictions for this one? My answer is x-5/x+1

Answer 22

repeat as before
take the denominator in factored form
set it equal to zero, solve for \(x\)

Answer 23

x=-1?

Answer 24

you obviously already factored the denominator as
\[(x+1)(x+9)\] solve
\[(x+1)(x+9)=0\] and solve for \(x\)

Answer 25

-1,-9

Answer 26

bingo

Answer 27

that is, those are the restricted values

Answer 28

ohh thank you:)

Answer 29

That's all for now

Answer 30

Simplify completely quantity 6 x minus 12 over 10.

Answer 31

is it 3(x-5)/5