Question

@empty hey hey

Answer 1

leggo

Answer 2

I didn't have the chance to till now, so now I'll dooooo it! \[W = \int\limits \vec F \cdot dr\]

Answer 3

Good luck I'll be watching haha.

Answer 4

Oh that dr should be a vector but w/e ok lol

Answer 5

\[\frac{ \vec dr }{ dt } = \vec r'(t) \implies \vec r'(t) dt\]

\[\vec r'(t) = <1,-2(t-2)>\]

\[W = \int\limits <0,-g> \cdot <1,-2(t-2)> dt\]

Answer 6

just seeing the drawing again XD

\[W = \int\limits_{0}^{4} (0) \vec i + (2g(t-2)) \vec j dt \]

Answer 7

is:
\[\Large {\mathbf{F}} = \left( {0, - mg} \right)\]?

Answer 8

Got 0? It's a made up question haha

Answer 9

But yeah it would be -mg otherwise

Answer 10

since, I see:
\[\Large {\mathbf{F}} = \left\langle {0, - g} \right\rangle \]

Answer 11

Yeah I just made this question up on the fly last night really late, so yeah throw an m in there haha.

Answer 12

hey empty quick question, I can't really remember, but would I have just a constant in the i direction as I'm integrating respect to 0