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Chemistry 13 Online
OpenStudy (vera_ewing):

What is the pH of a solution with [OH-] = 2.6 × 10^-3 M? A. 5.95 B. 2.59 C. 8.05 D. 11.41

OpenStudy (anonymous):

pOH = - log [OH-] pH = 14 - pOH did you get pOH?

OpenStudy (vera_ewing):

@JFraser It's C right?

OpenStudy (jfraser):

it's not C

OpenStudy (vera_ewing):

I mean A, not C. It's A right?

OpenStudy (jfraser):

nope

OpenStudy (vera_ewing):

Are you sure?

OpenStudy (jfraser):

do what @peachpi is saying i'm very sure

OpenStudy (jfraser):

find the pOH using the [OH-] concentration

OpenStudy (vera_ewing):

Hmm. I didn't get any of the answer choices. I got 16.35 when I did that :/

OpenStudy (vera_ewing):

Closest answer to that is D...so is D the answer?

OpenStudy (jfraser):

you're not even doing the right math, because it's a 2 step process

OpenStudy (jfraser):

find the -log(0.0026)

OpenStudy (jfraser):

that's the pOH

OpenStudy (vera_ewing):

Okay thank you.

OpenStudy (jfraser):

what do you get?

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