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To figure out the total joules of energy from water to ice at a given temperature and mass, you do 2 calculations. The first calculation is \(\bf q=m~x~C~x~\Delta T\) and it determines the amount of heat removed from water from18.1 °C to 0 °C for \(\bf \Delta T\). m is mass, C is specific heat capacity. The second calculation is to use \(\bf q=m~x~H_f\ and it determines the change of state between solid to liquid. m is mass and Hf stands for the heat of fusion of water and It should be given, -335 J/g.
the heat of fusion is negative 335 j/g because the liquid is freezing, going back. |dw:1436123790819:dw|
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