Question

If a meterstick moves to your right at a constant velocity of 0.8c, what would you measure its length to be?

Answer 1

@nincompoop

Answer 2

anyoneee

Answer 3

@aaronq

Answer 4

Length contraction

Answer 5

\[\huge L = \frac{ L_0 }{ \gamma } = L_0 \sqrt{1-\frac{ v^2 }{ c^2 }}\]

Answer 6

\[L_0\] is your proper length, L is the length observed by an observer in relative motion (respect to the object), v is your relative velocity, and finally c is the speed of light

Answer 7

yep that xD

Answer 8

I think the answers 0.6m, what do you think?

Answer 9

\[L_0 = 1m\]
\[v = 0.8c\] \[L = 1m \times \sqrt{1-\frac{ (0.8c)^2 }{ c^2 }} = \sqrt{1-\frac{ 0.64c^2 }{ c^2 }}m = 0.6m ~~ \checkmark\]

Answer 10

HUDDAH!

Answer 11

xD Thanks for le confirmation fwendo :D

Answer 12

Np :)

Answer 13

but just to be sure, do you cancel out the c^2 or smt?

Answer 14

Yes, it gets cancelled out

Answer 15

ah, thanks xD