how do you determine the intercepts from an equation or graph???

Question

owlcoffee · Answer

for the Y- intercept, you replace all the x's for zeroes, because any y-intercept has coordinates of (0,k) where "k" is a real number, for instance:
$$f:f(x)=e^x-u$$
This function will have a Y-intercept of "1-k" because by definition, you fin the Y-intercept by replacing all the x's for zero, in other words "f(0)":
$$f: f(0)=e^0-u$$
$$f:f(0)=1-u$$
So, we conclude that the function f intersects the y-axis on the point (0,1-u).

For the x-interception it's a little more complex, but easy as well, because it's pretty much the opposite of the y-interception, the x-interception points are often called "roots" or "zeroes" of the function. 
So, by definition a root point must have coordinates (k,0) where "k" is a real number, let's take for example:
$$g:g(x)=3x-9$$
In order to find the roots of this function we look for the values for "x" that make the whole function g equal zero, meaning "g(x)=0":
$$3x-9=0$$
And we solve for "x":
$$x=\frac{ 9 }{ 3 }$$
$$x=3$$
So, now we have found that the function g has it's x-interception on the coordinates (3,0).

anonymous · Answer

thank you so much :-)