Question

Given that D is equidistant to G and F, find m 10 years ago

Answer 1

@Michele_Laino @ganeshie8

Answer 2

since the point D is equidistant from G and F, then the line ED is the bisector of the angle GEF, then we can write this:
\[\Large 2x + 20 = 5x - 10\]
please solve for x

Answer 3

@Michele_Laino im stuck

Answer 4

subtractin 2x from both sides, we get:
\[\Large \begin{gathered}
2x + 20 - 2x = 5x - 10 - 2x \hfill \\
\hfill \\
20 = 3x - 10 \hfill \\
\end{gathered} \]
then adding 10 to both sides we get:
\[\Large \begin{gathered}
20 + 10 = 3x + 10 - 10 \hfill \\
\hfill \\
30 = 3x \hfill \\
\end{gathered} \]
now divide both sides by 3, what do you get?

Answer 5

subtracting*

Answer 6

so 10?

Answer 7

ok! we have x=10
so the measure of the angle GED, is:
(2*x+20)+(5*x-10)=(2*10+20)+(5*10-10)=...?

Answer 8

that's a lot of numbers I don't have much time I have like 17 left and a time limit!!

Answer 9

hint:
\[\begin{gathered}
\left( {2x + 20} \right) + \left( {5x - 10} \right) = \left( {2 \times 10 + 20} \right) + \left( {5 \times 10 - 10} \right) = ...? \hfill \\
= \left( {20 + 20} \right) + \left( {50 - 10} \right) = 40 + 40 = ...? \hfill \\
\end{gathered} \]

Answer 10

sorry, the angle GEF is 80 degrees, the measure of the angle GED is:
\[2x + 20 = 2 \times 10 + 20 = ...?\]

Answer 11

\[2x + 20 = 2 \times 10 + 20 = 20 + 20 = ...?\]